2[3z-(2z-3)]=3z-4

Solution for 2[3z-(2z-3)]=3z-4 equation:

Simplifying
2[3z + -1(2z + -3)] = 3z + -4

Reorder the terms:
2[3z + -1(-3 + 2z)] = 3z + -4
2[3z + (-3 * -1 + 2z * -1)] = 3z + -4
2[3z + (3 + -2z)] = 3z + -4

Reorder the terms:
2[3 + 3z + -2z] = 3z + -4

Combine like terms: 3z + -2z = 1z
2[3 + 1z] = 3z + -4
[3 * 2 + 1z * 2] = 3z + -4
[6 + 2z] = 3z + -4

Reorder the terms:
6 + 2z = -4 + 3z

Solving
6 + 2z = -4 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
6 + 2z + -3z = -4 + 3z + -3z

Combine like terms: 2z + -3z = -1z
6 + -1z = -4 + 3z + -3z

Combine like terms: 3z + -3z = 0
6 + -1z = -4 + 0
6 + -1z = -4

Add '-6' to each side of the equation.
6 + -6 + -1z = -4 + -6

Combine like terms: 6 + -6 = 0
0 + -1z = -4 + -6
-1z = -4 + -6

Combine like terms: -4 + -6 = -10
-1z = -10

Divide each side by '-1'.
z = 10

Simplifying
z = 10